$.ajaxSetup({contentType : "application/x-www-form-urlencoded;charset=utf-8",complete : function(xhr, textStatus) {if (xhr.status == 520) {//如果返回状态码是520window.location..reload();//刷新页面，执行登录逻辑return;}}});
java代码：
1. 写一个filter
import java.io.IOException;import javax.servlet.Filter;import javax.servlet.FilterChain;import javax.servlet.FilterConfig;import javax.servlet.ServletException;import javax.servlet.ServletRequest;import javax.servlet.ServletResponse;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;public class SessionTimeoutFilter implements Filter {public void destroy() {}public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {HttpServletRequest req = (HttpServletRequest) request;HttpServletResponse res = (HttpServletResponse) response;// 判断session里是否有用户信息if (req.getSession().getAttribute("username") == null){// 如果是ajax请求响应头会有，x-requested-with；if (req.getHeader("x-requested-with") != null && req.getHeader("x-requested-with").equalsIgnoreCase("XMLHttpRequest")){res.setStatus(520);//表示session timeout}else{chain.doFilter(req, res);}}else{chain.doFilter(req, res);}}public void init(FilterConfig chain) throws ServletException {}}
转载地址：/cxyj/p/3884964.html
如果觉得《Ajax请求Session超时解决》对你有帮助，请点赞、收藏，并留下你的观点哦！
