大一时候的期末大作业，一直没找到，在桌子缝里找到了优盘，现在才把内容放上来，希望能帮到你们。具体内容分为实验报告和程序具体代码。
程序设计基础
——期末大作业报告
实验设计
1.编写推箱子小游戏
2.使用C语言
3.使用Dev C++编程程序
4.实现小人移动判定
5.实现通关判定
实验分析
1.首先了解推箱子游戏的规则
2.使用代码完成基本的功能
3.判断移动是否正确
4.实现关卡之间的连接
5.判断游戏是否结束
6.尽量保证推箱子游戏的操作完整性
实现难点及解决方案
一、小人移动的判定
1. 该方向第一个方格为边界；
2. 该方向第一个方格是箱子，第二个方格是边界；
3.该方向第一个方格是箱子，第二个方格是放好位置的箱子；
4. 该方向第一个方格是箱子，第二个方格是箱子。
以上为小人无法移动的条件。
解决方案：
1. 人物移动时判断人物当前位置是空地还是目的地
2. 人物的移动的方向的前方是空地时可直接交换，
3. 人物的移动的方向的前方是箱子时需要再分几种情形
a. 箱子的前方是墙或箱子则无动作
b. 箱子的前方是空地则三者互换
c. 箱子的前方是目的地时则移动
二、地图的制作
1. 使用二维数组
2. 对游戏中的不同类型物体编号
3. 输出时根据数字不同输出不同形状：
1——墙
2——箱子
3——人物
4——目的地
部分代码如下：
（完整代码联系博主）
#include<stdio.h> #include<stdlib.h> #include<string.h> #include<conio.h> int i=0; int map_1[8][8]={{0,0,0,0,0,0,0,0},{0,1,1,1,1,1,1,0},{0,1,4,0,0,0,1,0},{0,1,0,2,0,0,1,0},{0,1,0,0,3,0,1,0},{0,1,0,0,0,0,1,0},{0,1,1,1,1,1,1,0},{0,0,0,0,0,0,0,0}}; int map_2[8][8]={{0,0,0,0,0,0,0,0},{0,0,0,0,1,1,1,0},{0,0,0,0,1,4,1,0},{0,0,0,0,1,0,1,0},{0,1,1,1,1,2,1,0},{0,1,3,0,0,0,1,0},{0,1,1,1,1,1,1,0},{0,0,0,0,0,0,0,0}}; int map_3[8][8]={{0,0,1,1,1,0,0,0},{0,0,1,4,1,0,0,0},{0,0,1,2,1,1,1,1},{1,1,1,0,0,2,4,1},{1,4,0,2,3,1,1,1},{1,1,1,1,2,1,0,0},{0,0,0,1,4,1,0,0},{0,0,0,1,1,1,0,0}}; int map_4[8][8]={{1,1,1,1,1,1,1,1},{1,0,0,4,0,0,0,1},{1,0,0,2,0,0,0,1},{1,0,0,0,0,2,4,1},{1,4,2,0,3,0,0,1},{1,0,0,0,2,0,0,1},{1,0,0,0,4,0,0,1},{1,1,1,1,1,1,1,1}};int map_5[8][8]={{1,1,1,1,1,1,1,1},{1,0,0,0,0,0,0,1},{1,1,0,0,0,0,0,1},{1,0,4,1,1,2,0,1},{1,0,0,1,3,0,0,1},{1,0,0,1,0,0,0,1},{1,0,0,1,0,0,0,1},{1,1,1,1,1,1,1,1}};int map_6[8][8]={{1,1,1,1,1,1,1,1},{1,0,0,0,0,0,0,1},{1,0,0,4,0,4,0,1},{1,0,0,2,0,2,0,1},{1,0,0,0,3,0,0,1},{1,0,0,2,0,2,0,1},{1,0,0,4,0,4,0,1},{1,1,1,1,1,1,1,1}}; int map_7[8][8]={{1,1,1,1,1,1,1,1},{1,4,4,4,1,1,1,1},{1,0,2,0,1,1,1,1},{1,0,3,0,1,1,1,1},{1,0,2,2,0,1,1,1},{1,0,0,0,1,1,1,1},{1,0,0,1,1,1,1,1},{1,1,1,1,1,1,1,1}};int map_8[8][8]={{1,1,1,1,1,1,1,1},{1,0,0,0,1,1,1,1},{1,4,0,2,1,1,1,1},{1,4,0,3,0,0,1,1},{1,1,2,0,1,0,1,1},{1,1,0,0,0,0,1,1},{1,1,1,1,1,1,1,1},};int map_9[8][8]={{1,1,1,1,1,1,1,0},{1,0,0,4,2,0,1,0},{1,0,1,0,0,0,1,0},{1,0,1,0,1,0,1,0},{1,0,0,3,1,0,1,0},{1,4,2,0,0,0,1,0},{1,0,1,1,1,1,1,0},{1,1,1,0,0,0,0,0},};int map_10[8][8]={{0,1,1,1,1,1,0,0},{0,1,0,0,1,1,1,0},{0,1,0,0,0,0,1,0},{1,1,1,3,1,0,1,1},{1,4,0,2,0,0,0,1},{1,4,2,0,0,1,0,1},{1,4,0,0,0,2,0,1},{1,1,1,1,1,1,1,1},};int x, y;int map[8][8] = {0};int shuchu(){for(x=0; x<8; x++){for(y=0; y<8; y++){if(map[x][y] == 1)printf("X "); if(map[x][y] == 3)printf("P "); if(map[x][y] == 2)printf("Q "); if(map[x][y] == 4)printf("B "); if(map[x][y] == 0)printf(" "); if(map[x][y] == 5) printf("V "); if(map[x][y] == 6) printf("M "); }printf("\n");}return 0;}int zhujiemian(){printf(" \n"" \n"" \n"" \n"" \n"" \n"" \n"" \n" " \n"" \n""welcome!\n"" \n"" \n"" R : replay \n"" WSAD : move \n""\n"" \n");}int find(){for(x=0; x<8; x++)for(y=0; y<8; y++){if(map[x][y] == 3||map[x][y] == 6)return 0;}return 0;}int count1(){int n=0;for(x=0; x<8; x++)for(y=0; y<8; y++){if(map[x][y] == 4)n++;}return n;}int count2(){int m=0;for(x=0; x<8; x++)for(y=0; y<8; y++){if(map[x][y] == 5)m++;}return m;}int up(){if(map[x][y] == 3) {if(map[x-1][y] == 0) {map[x-1][y] = 3;map[x][y] = 0;}if(map[x-1][y] == 2 && map[x-2][y] == 4) {map[x][y] = 0;map[x-1][y] = 3;map[x-2][y] = 5;}if(map[x-2][y] == 0 && map[x-1][y] == 2) {map[x][y] = 0;map[x-1][y] = 3;map[x-2][y] = 2;}else if(map[x-1][y] == 4){map[x][y] =0;map[x-1][y] = 6; }}else if(map[x][y] == 6){if(map[x-1][y] == 0) {map[x-1][y] = 3;map[x][y] = 4;}if(map[x-1][y] == 2 && map[x-2][y] == 4) {map[x][y] = 4;map[x-1][y] = 3;map[x-2][y] = 5;}if(map[x-2][y] == 0 && map[x-1][y] == 2) {map[x][y] = 4;map[x-1][y] = 3;map[x-2][y] = 2;}else if(map[x-1][y] == 4){map[x][y] =4;map[x-1][y] = 6; }}return 0;}int down(){if(map[x][y] == 3) {if(map[x+1][y] == 0){map[x+1][y] = 3;map[x][y] = 0;}if(map[x+1][y] == 2 && map[x+2][y] == 4) {map[x][y] = 0;map[x+1][y] = 3;map[x+2][y] = 5;}if(map[x+2][y] == 0 && map[x+1][y] == 2) {map[x][y] = 0;map[x+1][y] = 3;map[x+2][y] = 2;}else if(map[x+1][y] == 4){map[x][y] =0;map[x+1][y] = 6; }}else if(map[x][y] == 6){if(map[x+1][y] == 0) {map[x+1][y] = 3;map[x][y] = 4;}if(map[x+1][y] == 2 && map[x+2][y] == 4) {map[x][y] = 4;map[x+1][y] = 3;map[x+2][y] = 5;}if(map[x+2][y] == 0 && map[x+1][y] == 2) {map[x][y] = 4;map[x+1][y] = 3;map[x+2][y] = 2;}else if(map[x+1][y] == 4){map[x][y] =4;map[x+1][y] = 6; }}return 0;}
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