失眠网,内容丰富有趣,生活中的好帮手!
失眠网 > Watermelon

Watermelon

时间:2021-03-16 11:24:29

相关推荐

Watermelon

描述:

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showedwkilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.

Pete and Billy are great fans of even numbers, that's why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that's why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.

输入:

The first (and the only) input line contains integer numberw(1 ≤ w ≤ 100) — the weight of the watermelon bought by the boys.

输出:

PrintYES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; andNOin the opposite case.

样例输入:

8

样例输出:

YES

注释:

For example, the boys can divide the watermelon into two parts of 2 and 6 kilos respectively (another variant — two parts of 4 and 4 kilos).

描述:

一个炎热的夏日,皮特和他的朋友比利决定买一个西瓜。在他们看来,他们选择了最大最成熟的。然后称西瓜的重量,秤上显示重量为w公斤。他们迫不及待地赶回家,渴死了,决定把浆果分开,但他们面临着一个棘手的问题。

皮特和比利非常喜欢偶数,这就是为什么他们想要把西瓜分成两个部分,每个部分的重量都是偶数公斤,同时这两个部分并不一定是相等的。男孩们非常累,想尽快开始吃饭,这就是为什么你应该帮助他们,看看他们是否能按照他们想要的方式分西瓜。

输入:

第一行输入(有且只有一行)包括整数w(1 ≤ w ≤ 100)——男孩们买的西瓜的重量。

输出:

如果男孩们能把西瓜分成两个部分,每个部分的重量都是偶数公斤,输出YES;在相反的情况下则输出NO。

样例输入:

8

样例输出:

YES

注释:

例如,男孩们可以将西瓜分成两个部分,分别为2公斤和6公斤(另一种分法是分成4公斤和4公斤的两个部分)。

题目地址链接:Problem - A - Codeforces

如果觉得《Watermelon》对你有帮助,请点赞、收藏,并留下你的观点哦!

本内容不代表本网观点和政治立场,如有侵犯你的权益请联系我们处理。
网友评论
网友评论仅供其表达个人看法,并不表明网站立场。
相关阅读
watermelon的量词

watermelon的量词

2019-05-24

Codeforces——4A Watermelon

Codeforces——4A Watermelon

2023-11-09

Watermelon Count

Watermelon Count

2019-08-13

Watermelon CodeForces - 4A

Watermelon CodeForces - 4A

2020-02-04