断断续续搞了一个月反编译了一个被混淆的js算法，需要配合java使用。但是js里面使用了window.btoa,而ScriptEngine不支持window。解决的思路就是不用window自带的btoa。
btoa是创建一个base-64编码的字符串。
使用下面代码就能实现，从而代替btoa。
var base64EncodeChars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/";var base64DecodeChars = new Array(-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1,-1, -1, -1, -1, -1, -1, -1, -1, -1, -1, -1, 62, -1, -1, -1, 63,52, 53, 54, 55, 56, 57, 58, 59, 60, 61, -1, -1, -1, -1, -1, -1,-1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14,15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, -1, -1, -1, -1, -1,-1, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40,41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, -1, -1, -1, -1, -1);//编码的方法function base64encode(str) {var out, i, len;var c1, c2, c3;len = str.length;i = 0;out = "";while(i < len) {c1 = str.charCodeAt(i++) & 0xff;if(i == len){out += base64EncodeChars.charAt(c1 >> 2);out += base64EncodeChars.charAt((c1 & 0x3) << 4);out += "==";break;}c2 = str.charCodeAt(i++);if(i == len){out += base64EncodeChars.charAt(c1 >> 2);out += base64EncodeChars.charAt(((c1 & 0x3)<< 4) | ((c2 & 0xF0) >> 4));out += base64EncodeChars.charAt((c2 & 0xF) << 2);out += "=";break;}c3 = str.charCodeAt(i++);out += base64EncodeChars.charAt(c1 >> 2);out += base64EncodeChars.charAt(((c1 & 0x3)<< 4) | ((c2 & 0xF0) >> 4));out += base64EncodeChars.charAt(((c2 & 0xF) << 2) | ((c3 & 0xC0)>>6));out += base64EncodeChars.charAt(c3 & 0x3F);}return out;}//解码的方法function base64decode(str) {var c1, c2, c3, c4;var i, len, out;len = str.length;i = 0;out = "";while(i < len) {do {c1 = base64DecodeChars[str.charCodeAt(i++) & 0xff];} while(i < len && c1 == -1);if(c1 == -1)break;do {c2 = base64DecodeChars[str.charCodeAt(i++) & 0xff];} while(i < len && c2 == -1);if(c2 == -1)break;out += String.fromCharCode((c1 << 2) | ((c2 & 0x30) >> 4));do {c3 = str.charCodeAt(i++) & 0xff;if(c3 == 61)return out;c3 = base64DecodeChars[c3];} while(i < len && c3 == -1);if(c3 == -1)break;out += String.fromCharCode(((c2 & 0XF) << 4) | ((c3 & 0x3C) >> 2));do {c4 = str.charCodeAt(i++) & 0xff;if(c4 == 61)return out;c4 = base64DecodeChars[c4];} while(i < len && c4 == -1);if(c4 == -1)break;out += String.fromCharCode(((c3 & 0x03) << 6) | c4);}return out;}
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