题目:
阿里巴巴的食堂搞活动促销,已知某饮料一瓶三元钱,4个瓶盖可以换一瓶,2个空瓶可以换一瓶,则30元可以喝几瓶?
package ex栈;import java.io.*;import java.util.*;import java.text.*;import java.math.*;import java.util.regex.*;public class Main {/** 请完成下面这个函数,实现题目要求的功能 **//** 当然,你也可以不按照这个模板来作答,完全按照自己的想法来 ^-^ **/static int maxMount(int price, int cap, int emptyBottle, int money) {int beer = money / price;//初始的啤酒数int bottel = beer;//初始的瓶子数int cap1 = beer;//初始的瓶盖数int temp;while (cap1 >= cap || bottel >= emptyBottle) {if ((temp = cap1 / cap) > 0) {beer = beer + temp;cap1 = cap1 - cap * temp + temp;bottel = bottel + temp;}if ((temp = bottel / emptyBottle) > 0) {beer = beer + temp;cap1 = cap1 + temp;bottel = bottel - emptyBottle * temp + temp;}}return beer;}public static void main(String[] args){Scanner in = new Scanner(System.in);int res;int _price; _price = Integer.parseInt(in.nextLine().trim());//饮料单价int _cap;_cap = Integer.parseInt(in.nextLine().trim()); //4个瓶盖可以换一瓶int _emptyBottle;_emptyBottle = Integer.parseInt(in.nextLine().trim()); //2个空瓶换一瓶int _money;_money = Integer.parseInt(in.nextLine().trim()); //给定30元res = maxMount(_price, _cap, _emptyBottle, _money);System.out.println(String.valueOf(res)); }}
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