失眠网 > 获取url中的参数方法避免#的干扰删除url指定参数（vue hash模式有#删除指定参数问题）

获取url中的参数方法避免#的干扰删除url指定参数（vue hash模式有#删除指定参数问题）

时间：2020-12-13 12:22:24

function urlParse() {let url = window.location.search;let obj = {};let reg = /[?&][^?&]+=[^?&]+/g; // 正在表达式let arr = url.match(reg);// 得到数组：['?id=12345', '&a=b']if (arr) {arr.forEach(item => {let tempArr = item.substring(1).split('=');let key = decodeURIComponent(tempArr[0]);let val = decodeURIComponent(tempArr[1]);obj[key] = val;});}return obj;}

// 使用正则表达式来匹配全路径下的？后的参数，避免#的干扰const getUrlValue = function (name) {let href = location.hrefreturn decodeURIComponent((new RegExp('[?|&]' + name + '=' + '([^&;]+?)(&|#|;|$)').exec(href) || ["", ""])[1].replace(/\+/g, '%20')) || null}getUrlValue('inApp')

const getUrlParses = function () {var url = window.location.href// 如果url中没有传参直接返回空if (url.indexOf('?') === -1) {return null}var querys = url.substring(url.indexOf('?') + 1).split('&')var result = {}for (var i = 0; i < querys.length; i++) {var temp = querys[i].split('=')if (temp.length < 2) {result = null} else {result[temp[0]] = temp[1]}}console.log("getUrlParses -> result", result)return result}

删除url指定参数

function deleteParams(name){var loca = window.location;var baseUrl = loca.origin + loca.pathname + "?";var query = loca.search.substr(1);if (query.indexOf(name)>-1) {var obj = {}var arr = query.split("&");for (var i = 0; i < arr.length; i++) {arr[i] = arr[i].split("=");obj[arr[i][0]] = arr[i][1];};delete obj[name];var url = baseUrl + JSON.stringify(obj).replace(/[\"\{\}]/g,"").replace(/\:/g,"=").replace(/\,/g,"&");return url};}