后端开发|php教程
PHP如何接受ajax的post 表单并分行保存TXT呢
后端开发-php教程
JS代码如下
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function SubmitApply() { var form = Global.GetElement("#submitForm"); var UserName = Global.GetElement(form, input[name="Name"]).value; var Mobile = Global.GetElement(form, input[name="Tel"]).value; var Position = Global.GetElement(form, input[name="Position"]).value; var Company = Global.GetElement(form, input[name="Company"]).value; var ActId = Global.GetElement(form, input[name="Actid"]).value; if (Global.IsNullOrWhitesapce(UserName)) { Global.Tip.TipError("姓名必须填写"); return; } if (Global.IsNullOrWhitesapce(Mobile)) { Global.Tip.TipError("手机必须填写"); return; } if (/^1[3|4|5|8][0-9]\d{4,8}$/.test(Mobile) == false) { Global.Tip.TipError("手机格式不正确"); return; } var ajaxRequest = new HttpAjaxRequest(); ajaxRequest.ajax({ dataType: json, url: \, data: { name: UserName, mobile: Mobile, companyname: Company, position: Position, actid: ActId }, successed: OnSubmitAppplySuccesse, error: function () { Global.Tip.TipError(提交失败!); GlobalPlayer.DisableNext(); } });}/** * 名称：申请提交成功 */function OnSubmitAppplySuccesse(data) { if (data.Code == 0) { Global.Tip.TipMessage(提交成功!); var form = Global.GetElement("#submitForm"); GlobalPlayer.EnableNext(); GlobalPlayer.PlayNext(); form.reset(); } else { Global.Tip.TipError(提交失败! + data.Message); GlobalPlayer.DisableNext(); }}
哪个好人帮我写个完整的PHP接受源码吧 本人PHP小白（已哭晕）
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回复讨论(解决方案)
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在贴吧看到你了。。
ajaxRequest.ajax({
dataType: ‘json’,
url: ‘ ./save_to_txt.php’,
data: { name: UserName, mobile: Mobile, companyname: Company, position: Position, actid: ActId },
successed: OnSubmitAppplySuccesse,
error: function () {
Global.Tip.TipError(‘提交失败!’);
GlobalPlayer.DisableNext();
}
});
save_to_txt.php:
$name = $_POST[ ame];$mobile = $_POST[mobile];$companyname = $_POST[companyname];$actid = $_POST[actid];$position = $_POST[position]; $str =$name. "\n".$mobile."\n".$companyname."\n".$actid."\n".$position;$h = fopen(./t.txt,w);fwrite($h,$str);fclose($h);
在贴吧看到你了。。
ajaxRequest.ajax({
dataType: ‘json’,
url: ‘ ./save_to_txt.php’,
data: { name: UserName, mobile: Mobile, companyname: Company, position: Position, actid: ActId },
successed: OnSubmitAppplySuccesse,
error: function () {
Global.Tip.TipError(‘提交失败!’);
GlobalPlayer.DisableNext();
}
});
save_to_txt.php:
$name = $_POST[ ame];$mobile = $_POST[mobile];$companyname = $_POST[companyname];$actid = $_POST[actid];$position = $_POST[position]; $str =$name. "\n".$mobile."\n".$companyname."\n".$actid."\n".$position;$h = fopen(./t.txt,w);fwrite($h,$str);fclose($h);
大神啊 接收端不错 就是这个JS 发不出去数据 一直提交的是空数据是怎么回事呀
你没有指定工作方式，默认应该的 GET
用 $_POST 当然收不到数据
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