1.问题原因
默认情况下，jQuery传输数据使用Content-Type: x-www-form-urlencodedand和类似于"name=zhangsan&age=18"的序列，然而AngularJS，传输数据使用Content-Type: application/json和{ "name": "zhangsan", "age": "18" }这样的json序列。
2.解决办法
A.服务端进行修改，在Controller接收参数的方法中，对象前加 @RequestBody (注：要用对象的方式来接参数)
B.客户端修改
$http.post(url,{},{params:{"name": "zhangsan", "age": "18"}}).success(function(data){});$http.get(url,{params:{"name": "zhangsan", "age": "18"}}).success(function(data){});
C.修改Angular的$httpProvider的默认处理： //12/20/make-angularjs-http-service-behave-like-jquery-ajax/ （适用于post,推荐）
var starter = angular.module('module',['ionic','ui.router']).run(function(){});starter.config(['$httpProvider', function($httpProvider) {$httpProvider.defaults.headers.post['Content-Type'] = 'application/x-www-form-urlencoded;charset=utf-8';var param = function(obj) {var query = '', name, value, fullSubName, subName, subValue, innerObj, i;for(name in obj) {value = obj[name];if(value instanceof Array) {for(i=0; i<value.length; ++i) {subValue = value[i];fullSubName = name + '[' + i + ']';innerObj = {};innerObj[fullSubName] = subValue;query += param(innerObj) + '&';}}else if(value instanceof Object) {for(subName in value) {subValue = value[subName];fullSubName = name + '[' + subName + ']';innerObj = {};innerObj[fullSubName] = subValue;query += param(innerObj) + '&';}}else if(value !== undefined && value !== null)query += encodeURIComponent(name) + '=' + encodeURIComponent(value) + '&';}return query.length ? query.substr(0, query.length - 1) : query;};$httpProvider.defaults.transformRequest = [function(data) {return angular.isObject(data) && String(data) !== '[object File]' ? param(data) : data;}];}]);
如果觉得《AngularJs中$http发送post或者get请求 SpringMVC后台接收不到参数值的解决办法》对你有帮助，请点赞、收藏，并留下你的观点哦！
