失眠网,内容丰富有趣,生活中的好帮手!
失眠网 > python无限循环语句纵向输出字符串 python-urwid-无限循环的输出屏幕

python无限循环语句纵向输出字符串 python-urwid-无限循环的输出屏幕

时间:2023-05-31 12:05:06

相关推荐

python无限循环语句纵向输出字符串 python-urwid-无限循环的输出屏幕

我正在尝试使输出屏幕无尽循环.它需要输出来自另一个类的数据.

我现在发现的解决方案是:拥有一个带有队列属性的Printer类(用于实际输出类的测试替换器).当需要显示某些内容时,会将其附加到队列中.然后,有一个接口类-实际接口-带有自己的Printer实例.与MainLoop并行运行的线程检查队列中是否有项目,如果有,则将其输出.由于Printer的主要功能是无限循环,因此它也有自己的线程-在此测试中,它仅每隔几秒钟输出一次“ Hello”.

这是代码:

import urwid

import threading

import time

class Interface:

palette = [

('body', 'white', 'black'),

('ext', 'white', 'dark blue'),

('ext_hi', 'light cyan', 'dark blue', 'bold'),

]

header_text = [

('ext_hi', 'ESC'), ':quit ',

('ext_hi', 'UP'), ',', ('ext_hi', 'DOWN'), ':scroll',

]

def __init__(self):

self.header = urwid.AttrWrap(urwid.Text(self.header_text), 'ext')

self.flowWalker = urwid.SimpleListWalker([])

self.body = urwid.ListBox(self.flowWalker)

self.footer = urwid.AttrWrap(urwid.Edit("Edit: "), 'ext')

self.view = urwid.Frame(

urwid.AttrWrap(self.body, 'body'),

header = self.header,

footer = self.footer)

self.loop = urwid.MainLoop(self.view, self.palette,

unhandled_input = self.unhandled_input)

self.printer = Printer()

def start(self):

t1 = threading.Thread(target = self.fill_screen)

t1.daemon = True

t2 = threading.Thread(target = self.printer.fill_queue)

t2.daemon = True

t1.start()

t2.start()

self.loop.run()

def unhandled_input(self, k):

if k == 'esc':

raise urwid.ExitMainLoop()

def fill_screen(self):

while True:

if self.printer.queue:

self.flowWalker.append(urwid.Text(('body', self.printer.queue.pop(0))))

try:

self.loop.draw_screen()

self.body.set_focus(len(self.flowWalker)-1, 'above')

except AssertionError: pass

def to_screen(self, text):

self.queue.append(text)

class Printer:

def __init__(self):

self.message = 'Hello'

self.queue = []

def fill_queue(self):

while 1:

self.queue.append(self.message)

time.sleep(2)

if __name__ == '__main__':

i = Interface()

i.start()

它可以工作,但是对我来说似乎太混乱了,我担心它最终可能会成为某种编码恐怖.有没有更简单的方法来完成任务?

解决方法:

如果需要外部线程,请考虑以下代码.它设置一个队列,启动“发送当前时间到队列”线程,然后运行主界面.该接口会不时检查共享队列,并根据需要进行更新.

当接口退出时,外部代码会发信号通知线程要有礼貌地退出.

资源

import logging, Queue, sys, threading, time

import urwid

logging.basicConfig(

level=logging.DEBUG,

format="%(asctime)-4s %(threadName)s %(message)s",

datefmt="%H:%M:%S",

filename='trace.log',

)

class Interface:

palette = [

('body', 'white', 'black'),

('ext', 'white', 'dark blue'),

('ext_hi', 'light cyan', 'dark blue', 'bold'),

]

header_text = [

('ext_hi', 'ESC'), ':quit ',

('ext_hi', 'UP'), ',', ('ext_hi', 'DOWN'), ':scroll',

]

def __init__(self, msg_queue):

self.header = urwid.AttrWrap(urwid.Text(self.header_text), 'ext')

self.flowWalker = urwid.SimpleListWalker([])

self.body = urwid.ListBox(self.flowWalker)

self.footer = urwid.AttrWrap(urwid.Edit("Edit: "), 'ext')

self.view = urwid.Frame(

urwid.AttrWrap(self.body, 'body'),

header = self.header,

footer = self.footer)

self.loop = urwid.MainLoop(self.view, self.palette,

unhandled_input = self.unhandled_input)

self.msg_queue = msg_queue

self.check_messages(self.loop, None)

def unhandled_input(self, k):

if k == 'esc':

raise urwid.ExitMainLoop()

def check_messages(self, loop, *_args):

"""add message to bottom of screen"""

loop.set_alarm_in(

sec=0.5,

callback=self.check_messages,

)

try:

msg = self.msg_queue.get_nowait()

except Queue.Empty:

return

self.flowWalker.append(

urwid.Text(('body', msg))

)

self.body.set_focus(

len(self.flowWalker)-1, 'above'

)

def update_time(stop_event, msg_queue):

"""send timestamp to queue every second"""

logging.info('start')

while not stop_event.wait(timeout=1.0):

msg_queue.put( time.strftime('time %X') )

logging.info('stop')

if __name__ == '__main__':

stop_ev = threading.Event()

message_q = Queue.Queue()

threading.Thread(

target=update_time, args=[stop_ev, message_q],

name='update_time',

).start()

logging.info('start')

Interface(message_q).loop.run()

logging.info('stop')

# after interface exits, signal threads to exit, wait for them

logging.info('stopping threads')

stop_ev.set()

for th in threading.enumerate():

if th != threading.current_thread():

th.join()

标签:multithreading,urwid,python

来源: https://codeday.me/bug/1029/1958391.html

如果觉得《python无限循环语句纵向输出字符串 python-urwid-无限循环的输出屏幕》对你有帮助,请点赞、收藏,并留下你的观点哦!

本内容不代表本网观点和政治立场,如有侵犯你的权益请联系我们处理。
网友评论
网友评论仅供其表达个人看法,并不表明网站立场。