jl1=[];
for i=1:n
for j=1:n
jl1(j,i)=sqrt((X(i)-X(j))^2+(Y(i)-Y(j))^2+1);
end
end
jl1;
上面算法第四行结尾的数字1换成其他值为什么最后的运算结果是一样的？完整的程序如下：
[P1,F1]=uigetfile('*.txt','打开 GPS 水准点平面坐标文件');
fnal1=strcat(F1,P1);
fpath=P1;
fid1=fopen( fnal1,'r');
lineNum=0;
zbjz=[];
format long e
while (~feof(fid1))
curline = fgetl(fid1);
lineNum = lineNum + 1;
zbjz(lineNum,1)=1;
zbjz(lineNum,2)=str2num(curline(8:18));
zbjz(lineNum,3)=str2num(curline(20:31));
zbjz(lineNum,4)=str2num(curline(1:6));
end
zbjz;
Y=zbjz(:,2);
X=zbjz(:,3);
Z=zbjz(:,4);
o=zbjz(:,1);
n=length(X);
[P2,F2]=uigetfile('*.txt','打开 GPS 水准点大地高文件');
fnal2=strcat(F2,P2);
fpath1=P2;
fid2=fopen( fnal2,'r');
LineNum=0;
ddg=[];
while (~feof(fid2))
LineNum = LineNum + 1;
urline = fgetl(fid2);
ddg(LineNum,1)=str2num(urline(33:38));
end
ddg;
gcyc=ddg-Z;
jl1=[];
for i=1:n
for j=1:n
jl1(j,i)=sqrt((X(i)-X(j))^2+(Y(i)-Y(j))^2+1);
end
end
jl1;
aa=max(jl1);
aaa=max(aa);
b=aaa^2;
k=0;
for i=1:n
for j=1:n
B(j,i)=1-((X(i)-X(j))^2+(Y(i)-Y(j))^2+k^2)/b;
end
end
B;
% A1=pinv(S'*S)*S'*gcyc;
A=pinv(B)*gcyc;
A;
for i=1:n
for j=1:n
Qp(j,i)=1-((X(i)-X(j))^2+(Y(i)-Y(j))^2+k^2)/b;
end
end
Qp;
%水准点和已知点相同
yzdgcyc=Qp*A;
yzdnih=ddg-yzdgcyc;
v1=(Z-yzdnih)*1000;
shuizhun='已知水准点拟合高程(m)为';
fprintf('%s\n',shuizhun)
fprintf('%7.4f\n',yzdnih)
cancha1='已知点拟合残差(mm)为';
fprintf('%s\n',cancha1)
fprintf('%6.1f\n',v1)
neifuhe='内符合精度(mm)';
fprintf('%s\n',neifuhe)
miu=sqrt(sum(v1.*v1)/(n-1));
fprintf('%6.1f\n',miu)
[P,F]=uigetfile('*.txt','打开检核点平面坐标文件');
fnal=strcat(F,P);
fpath=P;
fid=fopen( fnal,'r');
lineNum=0;
jhzbjz=[];
format long e
while (~feof(fid))
curline = fgetl(fid);
lineNum = lineNum + 1;
jhzbjz(lineNum,1)=1;
jhzbjz(lineNum,2)=str2num(curline(8:18));
jhzbjz(lineNum,3)=str2num(curline(20:31));
jhzbjz(lineNum,4)=str2num(curline(1:6));
end
jhzbjz;
Y4=jhzbjz(:,2);
X4=jhzbjz(:,3);
Z4=jhzbjz(:,4);
o4=jhzbjz(:,1);
n2=length(X4);
[P4,F4]=uigetfile('*.txt','打开检核点大地高文件');
fnal4=strcat(F4,P4);
fpath4=P4;
fid4=fopen( fnal4,'r');
LineNum=0;
jhddg=[];
while (~feof(fid4))
LineNum = LineNum + 1;
urline = fgetl(fid4);
jhddg(LineNum,1)=str2num(urline(33:38));
end
jhddg;
gcyc1=jhddg-Z4;
jl11=[];
for i=1:n
for j=1:n
jl11(j,i)=sqrt((X(i)-X(j))^2+(Y(i)-Y(j))^2+1);
end
end
jl11;
bb=max(jl11);
bbb=max(bb)
for i=1:n2
for j=1:n
s(j,i)=1-((X4(i)-X(j))^2+(Y4(i)-Y(j))^2+k^2)/b;
end
end
% A=pinv(s'*s)*s'*gcyc;
for i=1:n2
for j=1:n
qq(j,i)=1-((X(j)-X4(i))^2+(Y(j)-Y4(i))^2+k^2)/b;
end
end
qq;
jhdgcyc=qq'*A;
jhdnih=jhddg-jhdgcyc;
v2=(Z4-jhdnih)*1000;
jianhedian='检核点拟合高程(m)为';
fprintf('%s\n',jianhedian)
fprintf('%7.4f\n',jhdnih)
cancha2='已知点拟合残差(mm)为';
fprintf('%s\n',cancha2)
fprintf('%6.1f\n',v2)
waifuhe='外符合精度(mm)';
fprintf('%s\n',waifuhe)
M=sqrt(sum(v2.*v2)/(n2-1));
fprintf('%6.1f\n',M)
%----求各等级残差----
jl12=[];
for i=1:n2
for j=1:n
jl12(j,i)=sqrt((X4(i)-X(j))^2+(Y4(i)-Y(j))^2);
end
end
jl12;
jl22=min(jl12);
sdcc=[];
sdcc=[];
jhcc=[];
for i=1:n2
sdcc(i)=12*sqrt(jl22(i)/1000);
sidcc(i)=20*sqrt(jl22(i)/1000);
jhcc(i)=30*sqrt(jl22(i)/1000);
end
sdcc;
sidcc;
jhcc;
cc=[sdcc;sidcc;jhcc];
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